=ln(5y^2+cos(5y))

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Solution for =ln(5y^2+cos(5y)) equation:


Simplifying
0 = ln(5y2 + cos(5y))

Remove parenthesis around (5y)
0 = ln(5y2 + cos * 5y)

Reorder the terms for easier multiplication:
0 = ln(5y2 + 5cos * y)

Multiply cos * y
0 = ln(5y2 + 5cosy)

Reorder the terms:
0 = ln(5cosy + 5y2)
0 = (5cosy * ln + 5y2 * ln)
0 = (5clnosy + 5lny2)

Solving
0 = 5clnosy + 5lny2

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5clnosy' to each side of the equation.
0 + -5clnosy = 5clnosy + -5clnosy + 5lny2
Remove the zero:
-5clnosy = 5clnosy + -5clnosy + 5lny2

Combine like terms: 5clnosy + -5clnosy = 0
-5clnosy = 0 + 5lny2
-5clnosy = 5lny2

Divide each side by '-5lnosy'.
c = -1o-1s-1y

Simplifying
c = -1o-1s-1y

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